next up previous
Next: Bibliography Up: A novel fiber-optic subscriber Previous: Computational Model

Results and Conclusions

For a sample network with typical values of various parameter as given in table I, results were computed. Main results are as follows. Without OAs only two branches can be supported. Each branch is assumed to have 32 users. In the case with unsaturated OAs, when first OA is placed, the optimal position is before first OADM. It increases the number of branches to 19. Second OA leads to maximisation of branches when placed before fifth OADM. After adding sixth OA only one branch adds up. With seventh OA, there is no increase in number of branches (It remains 38). Table II, III, IV, V and VI shows the results in tabular form.


  
Table I: Typical parameter values
Maximum allowed transmitter power PT 0 dBm
Desired Bit error rate   10-9
Insertion loss of single 2$\times$2 coupler Li 0.5dB
Fiber attenuation coefficient $\alpha$ 0.2 dB/km
Insertion loss of splice Lsp 0.5dB
Distance between branches L 5 km
Insertion loss for dropping signal in OADM L12 0.5dB
Insertion loss for passing signal in OADM Lm 0.7 dB
Receiver load resistance RL 100 $\Omega$
Operating wavelength $\lambda$ 1.55 $\mu$m
Optical Bandwidth Bo 25 GHz
Electrical Bandwidth Be 2.5 GHz
Receiver temperature T 300o K
Electron charge e 1.602$\times$10-19 C
Quantum efficiency of photodiode $\eta$ 1
Responsivity of photodiode Ro 1.28
Number of users per branch n 32


  
Table: Pe for without OA
$ \epsilon \rightarrow$ Pe
$ b \downarrow$ 0.00 0.05 0.10 0.15
1 $1.0\times 10^{-39}$ $8.1\times 10^{-33}$ $3.9\times
10^{-27}$ $1.9\times 10^{-22}$
2 $3.9\times 10^{-19}$ $6.1\times 10^{-16}$ $2.6\times
10^{-13}$ $3.9\times 10^{-11}$

b is number of branches, $\epsilon$extinction ratio


  
Table III: Number of supported branches after placing first ideal amplifier.
$ \epsilon \rightarrow$ Number of supported branches, Pe
$P \downarrow$ 0.00 0.05 0.10 0.15
I 19, 8.7 $\times 10^{-11}$ 18, 4.7 $\times 10^{-18}$ 18, 4.8 $\times 10^{-15}$ 18, 1.5 $\times 10^{-12}$
II 18, 8.9 $\times 10^{-21}$ 17, 4.7 $\times 10^{-18}$ 17, 4.8 $\times 10^{-15}$ 17, 1.8 $\times 10^{-12}$
III 17, 8.9 $\times 10^{-11}$ 16, 4.8 $\times 10^{-18}$ 16, 4.9 $\times 10^{-15}$ 16, 1.5 $\times 10^{-12}$

P is position of amplifier placement, $\epsilon$extinction ratio


  
Table: Pe with one optical amplifier
$ b \downarrow$ Pe
$ \epsilon \rightarrow$ 0.00 0.05 0.10 0.15
for b= 1 to 16, Pe is very small
17 2.8 $\times 10^{-45}$ 2.4 $\times 10^{-37}$ 7.4 $\times
10^{-31}$ 1.7 $\times 10^{-25}$
18 1.0 $\times 10^{-21}$ 4.7 $\times 10^{-18}$ 4.8 $\times 10^{-15}$ 1.5 $\times 10^{-12}$
19 8.9 $\times 10^{-11}$ $\ast$ $\ast$ $\ast$
20 $\ast$ $\ast$ $\ast$ $\ast$

b number of branches, $\ast$ means BER is greater than 10-9.


  
Table V: Supported b and Pe after second ideal amplifier
\begin{table}\footnotesize
\includegraphics[width=3.5in]{table.ps}$\otimes$\space means the $P_e > 10^{-9}$\space or amplifier cannot be placed.
\end{table}


  
Table VI: Number of supported branches vs. number of amplifiers
No. of amplifiers Supported branches after placing the amplifier at optimum position
5th 37
6th 38
7th 38

With a) average gain saturation as well as b) average gain saturation with gain fluctuation, the trend is similar. For the later case there is no improvement after placing more that three OAs.

In this work a novel subscriber access network architecture has been proposed and OA placement problem has been investigated. Cosidering the average gain fluctuation with gain fluctuation case, only three amplifier can be used. This means network can support 384 users per access fiber. The system will need 12 WDM channels while providing very good bandwidth (100Mbps) to each of the subscribers.


next up previous
Next: Bibliography Up: A novel fiber-optic subscriber Previous: Computational Model
Dr.Yatindra Nath Singh
2002-05-23