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Computational Model

In computation, one of the most important thing is loss model. If the transmitter power is known (say PT) and SOAs are not there between CO and receivers for which BER is computed, the loss (in dB) between transmitter and receiver assuming that receiver is in ithgroup starting from CO is given by
$\displaystyle L_{TR}=L_W + L_{sp} (2 i +5) +i \alpha l + (i-1) L_m +L_{12}$      
$\displaystyle + L_i \log_2 n + 10 \log_{10}n.$     (3)

In the above equation, LW is insertion loss of wavelength multiplexer at CO, Lsp splice loss, $\alpha$ fiber attenuation per unit length, L the length of fiber between two consecutive OADMs, Lm insertion loss of OADM, L12 insertion loss for drop signal in OADM, Li insertion loss of $2\times 2$ couplers used for making star coupler, and n the number of users in a group.

The loss (in dB) between transmitter at CO and first OA is used to find the input power to SOA. If the first SOA is placed before the ithgroup the loss between transmitter and first SOA is given by

\begin{displaymath}L_{TA_i} = L_W + 2iL_{sp} + i \alpha L + (i-1) L_m.
\end{displaymath} (4)

If the two consecutive amplifiers are placed before ith and jth OADM respectively, then loss (in dB) between them is given by

\begin{displaymath}L_{A_iA_j} = 2 (j-i) L_{sp} + (j-i) L_m + (j-i) \alpha L.
\end{displaymath} (5)

Further loss (in dB) between a receiver in lth branch and nearest amplifier (which is before tth OADM) is given by
$\displaystyle L_{A_tR} = \left [ 2 (l-t) +4 \right ] L_{sp} + (l-t) L_m +
L_{12} + (l-t) \alpha L$      
$\displaystyle + L_i \log_2 n + 10 \log_{10} n \hspace{0.3in} ; t < b$      
$\displaystyle = \left [ 2 (l-t) + 2 \right ] L_{sp} + (l-t) L_m + (l-t) \alpha L$      
$\displaystyle + L_i \log_2 n 10 \log_{10} n \hspace{0.3in}; t = b$     (6)

Here b is total number of branches in the network.

In order to compute the gain saturation, it is assumed that bits in all the channels are synchronised. In order to find the impact of other channels, two cases have been considered. In one case, average value of saturated gain has been used. In the other case BER for every bit pattern in interefering channels is computed. Thereafter, average BER is computed.


next up previous
Next: Results and Conclusions Up: A novel fiber-optic subscriber Previous: OA placement in proposed
Dr.Yatindra Nath Singh
2002-05-23